Math, asked by prdeep2081, 6 days ago

If sinA+cosB=1 and A=30 then value of B=

Answers

Answered by sahil95gupta
0

Answer:

60

Step-by-step explanation:

sin A + cos B = 1

sin 30 + cos B = 1

1/2. + cos B =1

cos B = 1-1/2

= 1/2

Answered by shabeehajabin
0

Answer:

If sinA+cosB=1 and A=30^\circ then the value of B=60^\circ.

Step-by-step explanation:

sinA+cosB=1 and given that the angle A=30^\circ. The question is to find the value of B.

So put the value of A in the equation, that is instead of sinA put sin(30).

Therefore the equation will become as follows,

  sin(30)+cosB=1

We know the value of sin(30) is equal to \dfrac{1}{2}. Put this value in the equation.

  \dfrac{1}{2} +cosB=1

Now take \dfrac{1}{2} to the right-hand side,

   cosB=1-\dfrac{1}{2}=\dfrac{1}{2}

Now we got the value of cosB is equal to \dfrac{1}{2}. From the trigonometric table, the value of \dfrac{1}{2} in terms of cos is given as, cos(60)=\dfrac{1}{2}

Hence the value of B=60^\circ.

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