Question

if sinA= cosB then prove that a+b =90​

Answer 1

Answer:

Step-by-step explanation:

ANSWER:-

We know the identity that:-

$\boxed{sin \theta = cos( 90 - \theta)}$

Using this Equation:-

We can also write the equation as:-

sinA = sin(90 - B)

So, as sin is common in both sides,

We can write this :-

A = 90 - B

Bringing B to this side,

we have proved that

$\boxed{\boxed{A+B=90}}$

HENCE PROVED!!

Things to Note:-

• Always remember the identity
• Sin and Cos are complementary of each other
• Tan and cot are complementary of each other
• Sec and Cosec are complementary of each other
• Complementary means whose sum equals 90 degree.
• Do not forget to mention theta , as without theta angles are incomplete.

Answer 2

YOUR QUESTION :

If sinA= cosB then prove that a+b =90

SOLUTION :

As we know that,

sinθ=cos(90−θ)

Using this Equation:-

sinA = sin(90 - B)

So, as sin is common in both sides,

We can write this :-

A = 90 - B

Bringing B to this side,

We have proved that,

$\boxed{\boxed{A+B=90}} </p><p>$

(HENCE PROVED)