if sina+cosec=2 THEN FIND sin^2016A +cosec^2016A
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2
Hey!!!!!
We have
sinA + cosecA = 2
=>sinA + 1/sinA = 2
=> sin²A + 1 = 2sinA
=> sin²A + 1 - 2sinA = 0
=> (sinA - 1)² = 0
=> sinA = 1
Thus A = 90°
Thus sin^2016 A + cosec^2016 A = 1 + 1
=> 2
Hope this helps you
We have
sinA + cosecA = 2
=>sinA + 1/sinA = 2
=> sin²A + 1 = 2sinA
=> sin²A + 1 - 2sinA = 0
=> (sinA - 1)² = 0
=> sinA = 1
Thus A = 90°
Thus sin^2016 A + cosec^2016 A = 1 + 1
=> 2
Hope this helps you
Answered by
0
__________________________________________________________
♦♦ ( sin A + cosec A ) = 2
=> ( sin² A + 1 ) = 2 sin A
=> ( sin² A - 2sin A + 1 ) = 0
=> ( sin A - 1 )² = 0
=> ( sin A ) = 1
_______________________________________________________
=> ( sin²⁰¹⁶ A + cosec²⁰¹⁶ A ) = ( 1 + 1 ) = 2
________________________________________________________
Cheers ♥ Amon
♦♦ ( sin A + cosec A ) = 2
=> ( sin² A + 1 ) = 2 sin A
=> ( sin² A - 2sin A + 1 ) = 0
=> ( sin A - 1 )² = 0
=> ( sin A ) = 1
_______________________________________________________
=> ( sin²⁰¹⁶ A + cosec²⁰¹⁶ A ) = ( 1 + 1 ) = 2
________________________________________________________
Cheers ♥ Amon
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