Math, asked by rekhathakur151278, 2 days ago

If SinA+ Cosec A = 2 then find the value of Sin³A + Cosec³A.

please help me with the answers. and say the correct answer only if you know.​

Answers

Answered by Anonymous
0

Answer:

a^3+b^3= (a+b)^3 -3ab(a+b)

here replace a with SinA and b with CosecA

(sinA+cosecA)^3 -3SinA CosecA (sinA+ CosecA)

=(2^3) - 3(2)

=8-6

=2

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