If SinA+ Cosec A = 2 then find the value of Sin³A + Cosec³A.
please help me with the answers. and say the correct answer only if you know.
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Answer:
a^3+b^3= (a+b)^3 -3ab(a+b)
here replace a with SinA and b with CosecA
(sinA+cosecA)^3 -3SinA CosecA (sinA+ CosecA)
=(2^3) - 3(2)
=8-6
=2
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