if sinA +cosecA =2 then find the value of sin^4 A + cosec^4A
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Given Equation is sin A + cosecA = 2.
On Squaring both sides, we get
(sinA + cosecA)^2 = (2)^2
sin^2a + cosec^2a + 2sinacoseca = 4
sin^2a + cosec^2a + 2 * sina * 1/sina = 4
sin^2a + cosec^2a + 2 = 4
sin^2a + cosec^2a = 2
Now,
On squaring both sides, we get
(sin^2a + cosec^2a)^2 = (2)^2
sin^4a + cosec^4a + 2sin^2a cosec^2a = 4
sin^4a + cosec^4a + 2 * 1 = 4
sin^4a + cosec^4a = 2.
Hope this helps!
On Squaring both sides, we get
(sinA + cosecA)^2 = (2)^2
sin^2a + cosec^2a + 2sinacoseca = 4
sin^2a + cosec^2a + 2 * sina * 1/sina = 4
sin^2a + cosec^2a + 2 = 4
sin^2a + cosec^2a = 2
Now,
On squaring both sides, we get
(sin^2a + cosec^2a)^2 = (2)^2
sin^4a + cosec^4a + 2sin^2a cosec^2a = 4
sin^4a + cosec^4a + 2 * 1 = 4
sin^4a + cosec^4a = 2.
Hope this helps!
siddhartharao77:
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5
Hi,
Please see the attached file!
Thanks
Please see the attached file!
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