Question

If SinA+ CosecA=2 then Sin n + Cosec n is equal to (a.)2 (b.)2 n (c.)4 n (d.)none of these. Explain the solution and how to solve it.

Answer 1

answer is a).2
sinA+cosecA=2
sinA+1/SinA=2
sin^2A+1=2sinA
(sinA-1)^2=0
sinA=1
A=90
sin N+cosecN= 2