Question

If sinA in right triangle =3/5 then what cosA

Answer 1

Given, sinA = 3/5

Now, cosA = √1-sin²A

= √1-(3/5)²

= √1- 9/25

= √(25-9)/25

= √16/25

= √(4/5)²

= 4/5 Ans.

Answer 2

Answer:

cosA is 4/5

Step-by-step explanation:

given that sinA=3/5=opposite side/hypotenus

opposite side=3    hypotenuse=5

adjacent side=root over 5sq-3sq

adjacent side=4

cosA is adjacent side/hypotenuse

cosA=4/5