Question

If sinA is 1/2 and cosB is 1/2 then find the value of tan(a+b)

Answer 1

Answer:

Solution,

sinA = 1/2

cosA = √1 - (sinA)² = √1- 1/4  = √3 / 2

cosB = 1/2

sinB = √1 -(cosB)² = √1 - 1/4 = √3 / 2

So, Tan (A+B) = [sin(A+B)/cos(A+B)]

= (sinAcosB+cosAsinB)/(cosAcosB - sinAsinB)

Now, use the value of sinA, cosB, sinA and cosB to find tan(A+B)

Alternative method:

sinA = 1/2

or, sinA = sin 30

or, A = 30

cosA = 1/2

or, cosA = cos 60 or, A = 60

Tan (A+B) = tan (30+60) =tan 90 = ∞

Step-by-step explanation: