Math, asked by dattatraykumbhar9921, 8 months ago

If sinA=(m-1)/(m+1) then prove that, tanA * cosecA=(m+1)/2√m​

Answers

Answered by MysteriousAryan
0

Answer:

we get sinA*(1-cosA)/(1+cosA)*(1-cosA)

now open all the brackets and we get

sinA-sinA.cosA/1-cos^2A

we can further simplify it as

sinA-sinAcosA/sin^2A

using identity(1-cos^2A=sin^2A)

now just divide both the terms by sin^2A

we get (1/sinA)-(cosA/sinA)

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