Question

If sinA=(m-1)/(m+1) then prove that, tanA * cosecA=(m+1)/2√m​

Answer 1

Answer:

we get sinA*(1-cosA)/(1+cosA)*(1-cosA)

now open all the brackets and we get

sinA-sinA.cosA/1-cos^2A

we can further simplify it as

sinA-sinAcosA/sin^2A

using identity(1-cos^2A=sin^2A)

now just divide both the terms by sin^2A

we get (1/sinA)-(cosA/sinA)