Question

If sinA+sin²A=1 and a cos¹²A+b cos⁸A+c cos⁶A−1=0 then b+ca+b=?

Answer 1

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Hi,

This is AbhijithPrakash,

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The answer for your question is as followed:

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sinA=1−sin²A  

sinA=cos²A

sin²A=cos⁴A

1−cos²A=cos⁴A

1=cos⁴A+cos²A

13=(cos⁴A+cos²A)3 by formula (a+b)³

1=cos¹²A+3cos¹⁰A+3cos⁸A+cos⁶A

Transverse 1 onto the other side we get the condition as given as in the question. Comparing the variables we get a=1, b=3, c=3, d=1 hence the value of

b+$\frac{c}{a}$+b = 3+31+1 =62 = 3

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Thanks,

Hope this Helps you.

Please mark it as Brainliest Answer....

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