Math, asked by anamramsha138, 10 months ago

if sinA + sin²A=1
and acos¹²A+bcos⁸A+ccos⁶A-1=0
find value of b+c/a+b​

Answers

Answered by Godlvl99
0

sinA + sin²A=1

acos¹²A+bcos⁸A+ccos⁶A-1=0

find value of b+c/a+b

(b + c)/(a + b) = (-2 (sqrt(5) - 2) a - sqrt(5) b + 3 b + 2 sqrt(5) + 4)/(2 (a + b)),         (b + c)/(a + b) = (2 (2 + sqrt(5)) a + (3 + sqrt(5)) b - 2 sqrt(5) + 4)/(2 (a + b))

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