Math, asked by EmanTahir4420, 10 months ago

If sina+sin2a+sin3a=1, then find the value of cos6a4cos4a+8cos2a is: a

Answers

Answered by itzJitesh

0

Answer:

inA + sin2A + sin3A = 1 => sinA + sin3A = 1 - sin2A => sinA ( 1+sin2A ) = cos2A => sinA ( 1 + 1 - cos2A ) = cos2A

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