Question

if sinA=sinB and cosA=cosB. then prove that A=2nπ+B​

Answer 1

Answer:

A = 2nπ + B

Step-by-step explanation:

The given Trigonometric equations are
sin A = sin B and cos A = cos B


The solution of sin A = sin B is

A = nπ + (-1)ⁿB, n is an integer....(1)

The solution of cos A = cos B is

A = 2nπ ± B , n is an integer........(2)

It is clear that required solution is common to both (1) and (2)

Therefore
A = 2nπ + B



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