Question

If sinA=sinB prove angle A is equal to angle B​

Answer 1

Step-by-step explanation:

Given: sinA = sinB

Proof:sinA = BC/AC

sinB = AB/AC

Since sinA = sinB,

BC/AC =AB/AC

Therefore, BC = AB

Hence ABC is an isoscelus triangle.

Therefore, angle A = angle B(angles opposite to equal sides are equal)

Hence proved