If sinA=sinB prove angle A is equal to angle B
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Step-by-step explanation:
Given: sinA = sinB
Proof:sinA = BC/AC
sinB = AB/AC
Since sinA = sinB,
BC/AC =AB/AC
Therefore, BC = AB
Hence ABC is an isoscelus triangle.
Therefore, angle A = angle B(angles opposite to equal sides are equal)
Hence proved
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