Question

If sinA + sinB + sinC =3 then what is the value of cosA + cosB + cosC = ?​

Answer 1

sinA + sinB + sinC = 3

sinA + sinB + sinC = 1+1+1

(sinA-1) + (sinB-1) + (sinC-1) = 0 --------(1)

comparing the both sides of equation (1)

sinA-1 = 0

sinA = 0

A = 90°

sinB-1 =0

sinB = 1

B = 90°

sinC-1 = 0

sinC = 1

C = 90°

Now,

cosA + cosB + cosC = ?

putting A + B + C = 90°

= cos 90° + cos 90° + cos 90°

= 0 + 0 + 0

= 0

Answer:-

cosA + cosB + cosC = 0

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Answer 2

Here is the answer ! Hope it helps.. :)