Math, asked by rockstarruchir007, 9 months ago

If sinA=X then cosA=
(A)√(1-x^2)
(B)X/√(1-x^2)
(C)1/x
(D){(1-x^2)^3/2}^1/3


Note :it's a multi answer question
and I also need explanation for every option​

Answers

Answered by nausinfatma
2

Step-by-step explanation:

sinA= X

√(1 - cos^2 A) = X

(1 - cos^2 A) = X^2 [by squaring both sides]

cos^2 A = 1 - X^2

cosA = √(1 - X^2)

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