Question

If sinA=x/y then find cosA×tanA in terms of x and y values?
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Answer 1

Answer:

~ Let's use simplify

☑️ Let us find the cosA first, and as we know that here we have to use cosA = ± √1 - sin²A.

Henceforth,

➝ cosA = ± √1 - (x/y)²

➝ cosA = ± √1 (y² - x²) / y²

➝ cosA = √ (y² - x²) / y Equation 1.

☑️ Let us find the tanA now, and as we know that here we have to use tanA = sinA / cosA

➝ tanA = (x/y) / [√(y²-x²)/y]

➝ tanA = x/√(y²-x²) Equation 2.

☑️ At last let use multiply Equation 1 and Equation 2.

➝ cosA × tanA = √ (y² - x²) / y × x/√(y²-x²)

Cancelling the digits.

➝ cosA × tanA = x/y

Hope it can help you!

Thank you!!

Answer 2

∠ABC is a right angle.

AC is the hypotenuse.

AB is known as the perpendicular.

BC is the base.

So according to the Pythagoras Theorem,

(AC)²=(AB)²+(BC)²