If sinB = 1/2, prove that : 3 cos B – 4cos3 B = 0
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I think your question is wrong
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Answered by
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sin B = 1/2
altitude = 1 hypotenuse = 2 base=?
base = √2²-1²
= √3
cos B = √3/2
3cos B - 4cos³ B
⇒ 3× √3/2 - 4×(√3/2)³
⇒ 3√3/2 - 4× 3√3/8
⇒12√3/8 - 12√3/8 (BY TAKING L.C.M.)
⇒0
HENCE PROVED.
HOPE IT HELPS :)
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