If sinB-=12/13then cotB is
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if sinB=12/13, ⇒p=12 &h=13
⇒by P.T. b=5
and cotb=cosb/sinb
⇒cotB=(5/13)/(12/13)=5/12
⇒by P.T. b=5
and cotb=cosb/sinb
⇒cotB=(5/13)/(12/13)=5/12
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13²=12²+x²
169=144+x²
169-144=x²
x=√25
x=5
opposite side=12
adjacent side=5
hypotenuse=13
cot B=adj/opp
=5/12
169=144+x²
169-144=x²
x=√25
x=5
opposite side=12
adjacent side=5
hypotenuse=13
cot B=adj/opp
=5/12
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