Question

if sinB = 3/5 and B is in the second quadrant, find the remaining trigonometric functions B​

Answer 1

Answer:

ANSWER

Given tanx=−

12

5

⇒cotx=−

5

12

But sec

2

=1+tan

2

x=1+

144

25

=

144

169

∴secx=±

12

13

Since x lies in the second quadrant, secx is negative

∴secx=−

12

13

⇒cosx=−

13

12

sinx=(tanx)(cosx)=(−

12

5

)(−

13

12

)=

13

5

⇒cscx=

5

13

.