Question

if SIN©=½ find the value of COS ©COSEC©​

Answer 1

Answer:

sin A = 1/2

p/h = 1/2

BC= 1 and AC = 2

H² = P²+B²

(2)² = (1)² + B²

4 - 1 = B²

B² = 3

B = √3

cosA = b/h

cos A = √3/2

cosec A = h/p

cosecA = 2

Hope this helps.....