Question

if since=1/2,then find value of 3 sina-4sina cube a.​

Answer 1

Answer:

The answer is 1

Step-by-step explanation:

Given $\sin A=\frac{1}{2}$

Therefore $3\sin A-4\sin^3A$

               $=3(\frac{1}{2})-4(\frac{1}{2})^3\\=\frac{3}{2}-4(\frac{1}{8})\\=\frac{3}{2}-\frac{1}{2}=\frac{3-1}{2}=\frac{2}{2}=1$

Just substitute the given value and simplify it