If sine alpha +cosec alpha=2 find the value of sine n alpha +cosec n alpha n belongs to z
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Step-by-step explanation:
Hello m.r
sinα+cosecα=2
sinα+
sinα
1
=2
sin
2
α+1=2sinα
sin
2
α−2sinα+1=0
(sinα−1)
2
=0
sinα=1
hence,
cosecα=
sinα
1
=1
now,
sin
n
α+csc
n
α=(1)
n
+(1)
n
=1+1=2
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