Question

If sine + cose = √4cos(e), (e 90°) then the value of tan(e) is ___

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Answer 1

Question :-

If sine + cose = √4cos(e), (e 90°) then the value of tan(e) is ___

Answer :-

As per sine, cosine and tangent formulas, we have here:

• Sine θ = Opposite side/Hypotenuse = BC/AC
• Cos θ = Adjacent side/Hypotenuse = AB/AC
• Tan θ = Opposite side/Adjacent side = BC/AB

We can see clearly from the above formulas, that:

• Tan θ = sin θ/cos θ

Now, the formulas for other trigonometry ratios are:

• Cot θ = 1/tan θ = Adjacent side/ Side opposite = AB/BC
• Sec θ = 1/Cos θ = Hypotenuse / Adjacent side = AC / AB
• Cosec θ = 1/Sin θ = Hypotenuse / Side opposite = AC / BC

The other side of representation of trigonometric values formulas are:

• Tan θ = sin θ/cos θ
• Cot θ = cos θ/sin θ
• Sin θ = tan θ/sec θ
• Cos θ = sin θ/tan θ
• Sec θ = tan θ/sin θ
• Cosec θ = sec θ/tan θ

Answered by - @MiѕѕGαямi

Answer 2

Answer:

As per sine, cosine and tangent formulas, we have here:

Sine θ = Opposite side/Hypotenuse = BC/ACCos θ = Adjacent side/Hypotenuse = AB/ACTan θ = Opposite side/Adjacent side = BC/AB

We can see clearly from the above formulas, that:

Tan θ = sin θ/cos θ

Now, the formulas for other trigonometry ratios are:

Cot θ = 1/tan θ = Adjacent side/ Side opposite = AB/BCSec θ = 1/Cos θ = Hypotenuse / Adjacent side = AC / ABCosec θ = 1/Sin θ = Hypotenuse / Side opposite = AC / BC

The other side of representation of trigonometric values formulas are:

Tan θ = sin θ/cos θCot θ = cos θ/sin θSin θ = tan θ/sec θCos θ = sin θ/tan θSec θ = tan θ/sin θCosec θ = sec θ/tan θ