Question

If sine theta -cos theta= 0,0°< theta <90°. then find the value of theta​

Answer 1

Answer:

Theta = π/4

Step-by-step explanation:

Answer 2

Answer:

Theta = 45°

Step-by-step explanation:

Sin∅ - Cos∅ = 0

or, (sin∅)² - 2sin∅cos∅ + (cos∅)²=0

or, sin²∅+cos²∅-2sin∅cos∅=0

or, 1 -2sin∅cos∅ = 0    [ As we know, sin²∅+cos²∅ = 1 ]

or, 2sin∅cos∅ = 1  

or, sin2∅= 1           [2sin∅cos∅ = sin2∅]

or, 2∅= $sin^(-1)$ (1)

or, 2∅ = 90°

or, ∅ = 45°

and 0°<45°<90°