Question

If sine theta is equal to 3 by 5 and cos theta is equal to 4 by 5 find the value of sine squared theta plus cos square theta?​

Answer 1

sine theta is equal to=3/5

cos theta is equal to=4/5

sin squared theta+cos square theta=3/5 hole square+4/5 hole square

9/25+16/25

9+16/25=25/25=1

Answer 2

Appropriate Question :-

If Sin θ is equal to $\displaystyle \frac{3}{5}$ and Cos θ is equal to $\displaystyle \frac{4}{5}$. Find the value of Sin² θ + Cos² θ

$\:$

Step-by-step Explanation :-

Given :-

• Sin θ is equal to $\displaystyle \frac{3}{5}$ and Cos θ is equal to $\displaystyle \frac{4}{5}$.

$\:$

To Find :-

• What is the value of Sin² θ + Cos² θ

$\:$

Solution :-

Given :

• $\bf \: {Sin \: θ \: = \: \displaystyle \bf\frac{3}{5} }$

$\:$

• $\bf \: {Cos \: θ \: = \: \displaystyle \bf\frac{4}{5} }$

$\:$

$\: \: \: ⇢ \: \: \: \bf \: Sin^{2} \: \theta \: + \: Cos^{2} \: \theta$

$\:$

$\: \: \displaystyle \: \: \: ⇢ \: \: \: \sf \: \bigg( \frac{3}{5} \bigg) ^{2}\: + \: \bigg( \frac{4}{5} \bigg) ^{2}$

$\:$

$\: \: \: \displaystyle \: \: \: ⇢ \: \: \: \sf \: \bigg( \frac{9}{25} \bigg) + \bigg( \frac{16}{25} \bigg)$

$\:$

$\: \: \: \: \: \displaystyle \: \: \: ⇢ \: \: \: \sf \: \frac{9 + 16}{25} \:$

$\:$

$\: \: \: \: \: \: \: \displaystyle \: \: \: ⇢ \: \: \: \sf \: \cancel \frac{25}{25}$

$\:$

$\: \: \: \: \: \: \: \: \displaystyle \: \: \: ⇢ \: \: \: \sf \: \bf \red 1$

$\:$

∴ The value of Sin² θ + Cos² θ is 1 .

$\:$