Question

If sino = 1/2 then the value of coso = ?​

Answer 1

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Let,

The side opposite to angle θ =AB = 3k

The side adjacent to angle θ =BC = 4k

where k is any positive integer Firstly we have to find the value of AC.

So, we can find the value of AC with the help of Pythagoras theorem

⇒ (AB)2 + (BC)2 = (AC)2

⇒ (3k)2 + (4k)2 = (AC)2

⇒ (AC)2 = 9 k2+16 k2

⇒ (AC)2 = 25 k2

⇒ AC =√25 k2

⇒ AC =±5k

But side AC can’t be negative.

So, AC = 5k

Now, we will find the sin θ and cos θ Side opposite to angle θ = AB = 3k and Hypotenuse = AC = 5k

Answer 2

Let,

The side opposite to angle θ =AB = 3k

The side adjacent to angle θ =BC = 4k

where k is any positive integer Firstly we have to find the value of AC.

So, we can find the value of AC with the help of Pythagoras theorem

⇒ (AB)2 + (BC)2 = (AC)2

⇒ (3k)2 + (4k)2 = (AC)2

⇒ (AC)2 = 9 k2+16 k2

⇒ (AC)2 = 25 k2

⇒ AC =√25 k2

⇒ AC =±5k

But side AC can’t be negative.

So, AC = 5k

Now, we will find the sin θ and cos θ Side opposite to angle θ = AB = 3k and Hypotenuse = AC = 5k