Question

If sino = nsin (thita+2 a) then tan (thita + a)
is equal to​

Answer 1

Answer:

Correct option is

A

1−n

1+n

tanα

sinθ=nsin(θ+2α)

sin(θ+2α)

sinθ

=n

apply componendo dividendo rule,

sinθ−sin(θ+2α)

sinθ+sin(θ+2α)

=

n−1

n+1

apply sinC+sinD and sinC−sinD

2sinαcos(θ+α)

2sin(θ+α)cosα

=

n−1

n+1

tanα

tan(θ+α)

=

n−1

n+1

tan(θ+α)=

n−1

n+1

tanα