If ,
sinø=1/√5 then will,,
cosø=2/√10???
Give the Equation.[Must]
Correct Answer Needed,,,No Spamming Plz
Answers
Answered by
10
Hi friend,
Sin@ = 1/✓5 = P/H
P = 1 , H = ✓5 , B = ?
We know that,
(H)² = (B)² + (P)²
(✓5)² = (B)² + (1)²
(B)² = (✓5)² - (1)²
(B)² = 5-1
(B)² = 4
B = ✓4 = 2
Therefore,
Cos@ = B/H = 2/✓5
Hence,
Cos@ is not equal to 2/✓10
Sin@ = 1/✓5 = P/H
P = 1 , H = ✓5 , B = ?
We know that,
(H)² = (B)² + (P)²
(✓5)² = (B)² + (1)²
(B)² = (✓5)² - (1)²
(B)² = 5-1
(B)² = 4
B = ✓4 = 2
Therefore,
Cos@ = B/H = 2/✓5
Hence,
Cos@ is not equal to 2/✓10
Anonymous:
Thanks sir/madam
Answered by
5
Hi there!
•sinø = 1/√5 = Perpendicular / Hypotenuse
Hence, Perpendicular = 1
Hypotenuse = √5
Base = ?
For finding the value of base we can use Pythagoras theorem,
(Base)² = (Hypotenuse)² - (Perpendicular)²
(Base)² = (√5)² - (1)²
(Base)² = 5 - 1
(Base)² = 4
Base = √4
Base = 2
Now,
• cosø = Base / Hypotenuse
cosø = 2 / √5
Therefore, cosø ≠ 2/√10
HOPE IT HELPS!
•sinø = 1/√5 = Perpendicular / Hypotenuse
Hence, Perpendicular = 1
Hypotenuse = √5
Base = ?
For finding the value of base we can use Pythagoras theorem,
(Base)² = (Hypotenuse)² - (Perpendicular)²
(Base)² = (√5)² - (1)²
(Base)² = 5 - 1
(Base)² = 4
Base = √4
Base = 2
Now,
• cosø = Base / Hypotenuse
cosø = 2 / √5
Therefore, cosø ≠ 2/√10
HOPE IT HELPS!
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