Question

if sinø =3/5, find the value of 3tanø+5cosø/5secø-3cotø​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

We have 

sinθ=5/4⇒hypotenuseperpendicular=5/4 

so , we contract a right triangle ABC  , right angle at B such that ∠BAC=θ  , perpendicular  = BC  = 4  and Hypotenuse  = AC = 5 

By pythagoras theorem  , we have 

AC2=AB2+BC2 

⇒.5/2=AB2+42 

⇒AB2 = 25 - 16 = 9 

⇒AB=9=⇒ AB  = 3 

∴cosθ=AC/AB=5/3,tanθ=AB/BC=3/4 

cotθ=AC/AB=4/3,secθ=AB/BC=3/4

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