if sinø =cos(theta-6). find the value of theta
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48°................
sinθ=cos(θ-6)
or,cos(90-θ)=cos(θ-6)
or,90-θ=θ-6
or,2θ=96
or,θ=48°
if,sin(fai)=cos(θ-6)
or,cos(90-fai)=cos(θ-6)
or,90-fai=θ-6
or,θ=96-fai
hope you like it
if it helps you please mark the answer as brainliest answer
sinθ=cos(θ-6)
or,cos(90-θ)=cos(θ-6)
or,90-θ=θ-6
or,2θ=96
or,θ=48°
if,sin(fai)=cos(θ-6)
or,cos(90-fai)=cos(θ-6)
or,90-fai=θ-6
or,θ=96-fai
hope you like it
if it helps you please mark the answer as brainliest answer
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