If sinø+cosø=root3 then prove that tan ø+cosø=1
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sinθ+cosθ=3
=(sinθ+cosθ)2=3
=sin2θ+cos2θ+2sinθcosθ=3
⇒2sinθcosθ=2
⇒sinθcosθ=1
⇒sinθcosθ=sin2θ+cos2θ
⇒1=sinθcosθsin2θ+cos2θ
⇒tanθ+cotθ=1
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Answer:
sinθ+cosθ= √3
Squaring both sides
=(sinθ+cosθ)²=3
=sin²θ+cos²θ+2sinθcosθ=3
⇒1+2sinθcosθ=3 (°.°sin²θ+cos²θ=1)
⇒sinθcosθ=1
⇒sinθcosθ=sin²θ+cos²θ
(°.°sin²θ+cos²θ=1)
⇒1=sin²θ+cos²θ/sinθcosθ
⇒tanθ+cotθ=1
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