Question

if sinQ=4/5 find the value of sinQ.tanQ-1/2tan2Q​

Answer 1

Step-by-step explanation:

HOPE IT HELPS ❣️❣️

PLEASE FOLLOW ME AND MARK AS BRANLIEST....

Answer 2

Answer:

Required value is $\frac{97}{80}$

Step-by-step explanation:

We know,

$\tan(q) = \frac{ \sin(q) }{ \sqrt{1 - \sin {}^{2} (q) } }$

And

$tan(q) = \frac{ \frac{4}{5} }{ \sqrt{1 - \frac{16}{25} } } = \frac{ \frac{4}{5} }{ \frac{3}{5} } = \frac{4}{5} \times \frac{5}{3} = \frac{4}{3}$

And

$tan(2q) = \frac{2 \tan(q) }{1 - { \tan{2} (q) }}$

$\tan(2q) = \frac{2 \times \frac{4}{3} }{1 - \frac{16}{9} } = \frac{ \frac{8}{3} }{ \frac{-7}{9} } = \frac{8}{3} \times \frac{-9}{7} = \frac{-24}{7}$  

$sinQ.tanQ-1/2tan2Q = \frac{4}{5} \times \frac{4}{3} - \frac{1}{2} \times \frac{-7}{24} = \frac{16}{15} + \frac{7}{48} = \frac{ 291}{240} = \frac{97}{80}$

Required value is $\frac{97}{80}$