Question

if sinteta+costeta =root2 then evaluate tantheta +cot tetha

Answer 1

Hello friend....

here given ...
sin θ + cos θ = √2

we have to find
tanθ + cot θ =?

solution:-
sin θ + cos θ = √2
now square on both side
= ( sin θ + cos θ )² = √2²
= (sin² θ + cos² θ )+ 2 sin θ cos θ = 2
= 1+ 2sin θ cos θ = 2
=> sin θ cos θ = 1/2

now

tanθ + cot θ =sin θ/cos θ + cos θ/sin θ
=( sin² θ +cos² θ) / sin θ cos θ
= 1 / (1/2) = 2 answer

♦♦ hope it helps ♦

Answer 2

Hey, check the attachment please