if sinteta+costeta=root3,then prove that tanteta+cotteta=1
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Answer:
sin@+cos@ = √3
(sin@+cos@)² = √3²
=> sin²@+2sin@cos@ +cos²@=3
=> 1+2sin@cos@=3
=> 2sin@cos@=2
=> sin@cos@ =1
we have
tan@+cot@
= sin@/cos@ + cos@/sin@
= (sin²@+cos²@)/sin@cos@
= 1/1
=1
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