Question

if sintheeta and costheeta are the root of the equation√3x²+kx+3=0 then find the value of k

Answer 1

Answer:

root3x²+kx+3=0

b²-4ac

k²-4(root3)(3)

k²-12root3=0

k²=12root3

k=root4x3xroot3

k=2root3

k=±2root3