Question

if sintheta and costheta are the roots of the equation x^2 + px + q=0 then p^2 =
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Answer 1

Answer:

Let me assume theta is a

Sina+cosa=-b/a

Sina*cosa=c/a

By applying (A+B)^2 formulae

By A is sina, B is cosa

(Sina+cosa)^2=sin^2a+cos^2a +2sinacosa

Step-by-step explanation:

Answer 2

Answer:

p^2 = ( sinx + cosx )^2

Step-by-step explanation:

x^2 + px + q =0 _1

( x - sinx )( x - cosx ) = 0 as sinx and cosx are roots

x^2 -x( sinx + cosx ) + sinx.cosx = 0 _2

Comparing 1 and 2

p = -( sinx + cosx )

p^2 = ( sinx + cosx )^2

Hope it helps UwU