if sintheta + cos theta = root2 the prove that tan theta + cot theta =2
Answers
Answered by
2
Answer:
here given ...
sin θ + cos θ = √2
we have to find
tanθ + cot θ =?
solution:-
sin θ + cos θ = √2
now square on both side
= ( sin θ + cos θ )² = √2²
= (sin² θ + cos² θ )+ 2 sin θ cos θ = 2
= 1+ 2sin θ cos θ = 2
=> sin θ cos θ = 1/2
now ,
tanθ + cot θ =sin θ/cos θ + cos θ/sin θ
=( sin² θ +cos² θ) / sin θ cos θ
= 1 / (1/2) = 2 answer
Step-by-step explanation:
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Answered by
1
Answer:
sin@ + cos@ = √2
=> sin²@ + 2sin@cos@ + cos²@ = 2
=> 1+2sin@cos@ = 2
=> 2sin@cos@ = 1
=> sin@cos@ = 1/2 ........... @1
=> tan@ + cot@
= sin@/cos@ + cos@/sin@
=(sin²@ + cos²@)/sin@cos@
= 1/sin@cos@
=>1/(1/2) (from equation 1)
=2
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