If sintheta + cosectheta = 2 then show that sin⁷ + cosec⁷theta =?If sin + cosectheta = 2 then show that sin⁷theta + cosec⁷theta =?
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Solution :-
→ sinA + cosecA = 2
Putting cosecA = 1/sinA in LHS we get,
→ sinA + 1/sinA = 2
Taking LCM now,
→ (sin²A + 1)/sinA = 2
→ (sin²A + 1) = 2sinA
→ sin²A - 2sinA + 1 = 0
→ sin²A - 2*1*sinA + 1² = 0
comparing with a² - 2ab + b² = (a - b)² we get,
→ (sinA - 1)² = 0
or,
→ sinA - 1 = 0
→ sinA = 1
Therefore,
→ cosecA = 1/sinA= 1/1 = 1
Now,
→ sin⁷A + cosec⁷A
→ (1)⁷ + (1)⁷
→ 1 + 1
→ 2 (Ans.)
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