Question

If sinthita=2/3 find all trigonometric ratios​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

If sin thita is 2/3

Then, the sin thita =P/H

So, the perpendicular is 2 and hypotenuse is 3.

Now, we find the base,

By Pythagoras theorem,

(perpendicular) ²+(base) ²=(hypotenuse) ²

(2) ²+(base) ²=(3) ²

4+(base) ²=9

(base) ²=9-4

(base) ²=5

base=√5

all trignometric ratios,

cos thita=B/H

√5/3

tan thita=P/B

2/√5

cosec thita=H/P

3/2

sec thita=H/B

3/√5

cot thita=B/P

√5/2

I hope this will help you.