if sinthita+costhita=
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sinthita+costhita=>=root(2).
step by step---
sinx + cosx = √2(sinx/√2 + cosx/√2) = √2 [sin(x+pi/4] Hence |sinx+cosx| = √2|sin(x+pi/4)|, which is ≤√2. ... For sin(thita)+cos(thita)>=0,it is sin(thita)+cos(thita)----(1) , But for sin(thita)+cos(thita)<0 ,it is -(sin(thita)+cos(thita))------(2)
(I) and (ii) =>=root(2).
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Answer:
Sinthita + costhita is equal to the above images it will clear
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