Question

if sintita=a/b then tantita =​

Answer 1

Step-by-step explanation:

We know,

sin theta = opp. side / hypotenuse

= a/b

Iᑎ ᖇIᘜᕼT ᗩᑎᘜᒪᗴᗪ TᖇIᗩᑎᘜᒪᗴ,

hyp^2 = (side1)^2 + (side2)^2

let the other side (adjacent to angle) be c

${b}^{2} = {a}^{2} + {c}^{2}$

$c = \sqrt{( {b}^{2} - {a}^{2} } )$

tan theta = opp. side/adjacent side

$\tan(theta) = \frac{a}{ \sqrt{( {b}^{2} - {a}^{2} } )}$