Question

if sintita+costita=m and sectita+cosectita=n.then prove that n(m2-1)=2m​

Answer 1

Answer:

sina+cosa=m

seca+coseca=n

n(m²-1)

=(seca+coseca){(sina+cosa)²-1}

=(sina+cosa/sinacosa)(2sinacosa)

=2(sina+cosa)

=2m