Question

if sinx = 1/2 and cosx = -√3/2 then general value of x is​

Answer 1

Answer:

The equation holds if

∣cosx∣=

1

i.e. if

x=

nπ,n∈

I

If

∣cosx∣=

1

then

sin 2

2

3

sinx+

2

1

=

0

⇒ sinx= 1

2

1

But

sinx=

1

as in that case

cosx=

0

∴ sinx=

2

1

⇒ x= nπ+

(−1) n

6

π

please mark as brailniest

Answer 2

Step-by-step explanation:

∴sinx=

2

1

⇒x=nπ+(−1)

n

6

π