Question

If sinx= 1/3,show that cosxcosecx + tanx secx = 16√2+3 /8​

Answer 1

Answer:

sin x=1/3, cos x=√(1-sin^2x)=√(8/9)=2√2/3

tan x=1/(2√2)

Substitute these values in the above expression

(2√2/3)(3)+(1/2√2)(3/2√2)

2√2+(3/8)

=(16√2+3)/8