If sinx=1/6,find value of sin3x
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Answered by
32
sin3x = 3sinx - 4sin³x
=3×1/6 - 4×(1/6)³
=1/2 -4/216
=1/2 -1/54 = 26/54 = 13/27
=3×1/6 - 4×(1/6)³
=1/2 -4/216
=1/2 -1/54 = 26/54 = 13/27
BhuvanSingla:
Why sin3x=3sinx-4sin^3x?
you can proof this as sin3x= sin(2x+x) =sin2xcosx +cos2xsinx
and sin2x= 2sinxcosx and cos2x= 1- 2sin^2x
hope now you understand the derivation :)
and sin2x= 2sinxcosx and cos2x= 1- 2sin^2x
hope now you understand the derivation :)
Answered by
5
Sinx=1/6 sin3x=3sinx_4(sinx)cube
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