If sinx = 2cosx, the value of sin2x is
(A) 1/3
(B) 2/3
(C)-4/3
(D) 4/5
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HELLO DEAR,
given:- sinx = 2cosx
=> tanx = 2 = p/b
by Pythagoras theorem,
h = √5
so, sinX = 2/√5 & cosX = 1/√5
as, we know:- sin2∅ = 2sin∅cos∅
therefore, sin2X = 2sinXcosX
=> 2 * (2/√5) * (1/√5)
=> 4/5
hence, option (D) is correct
I HOPE IT'S HELP YOU DEAR,
THANKS
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