Question

if SinX=a and SecX=b,find the value of CotX.

Answer 1

Answer:

$\large\boxed{\sf{\dfrac{1}{ab}}}$

Step-by-step explanation:

Given

$\sin(x) = a$

and

$\sec(x) = b$

To find the value of cot x

We know that

$\sec(x) = \dfrac{1}{ \cos(x) }$

Therefore, we get

$= > \cos(x) = \dfrac{1}{b}$

Also, we know that

$\cot(x) = \dfrac{ \cos( x) }{ \sin(x) }$

Therefore, we will get

$= > \cot(x) = \dfrac{ \frac{1}{b} }{a} \\ \\ = > \cot(x) = \dfrac{1}{ab}$