If sinx= and x lies in second quadrant find the value of sin x/2
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Take a triangle A,B,C.
sin x =1/4
opposite side =1, Hypotenuse =4.
adjacent side = √(4)²-(1)²
= √16-1=√15
cos x= √15/4
2sin²x/2=1-cosx
2sin²x/2=1-cosx
= 1-√15/4
=4/4-√15/4
sin²x/2=4-√15/8
sin x/2=√4-√√15/8
similary find tan x/2 and cos x/2
sin x =1/4
opposite side =1, Hypotenuse =4.
adjacent side = √(4)²-(1)²
= √16-1=√15
cos x= √15/4
2sin²x/2=1-cosx
2sin²x/2=1-cosx
= 1-√15/4
=4/4-√15/4
sin²x/2=4-√15/8
sin x/2=√4-√√15/8
similary find tan x/2 and cos x/2
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