Question

If sinx = Asin(x+y). Then find the value of tan(x+y)
a) siny/(siny-A)
b) sinxcosx/(Acosy-sin²x)
c) sinxcosx/(Acosy+sin²x)
d) sinx/(cosx-A)

​

Answer 1

Answer:

sin(x+y)/sin(x-y) = (a+b)/(a-b) =>

(sinxcosy+cosxsiny)/(sinx.cosy-cosxsiny)

= (a+b)/(a-b) . Dividing both numerator and the denominator of LHS with cosx.cosy we get

(tanx+tany)/(tanx- tany)= (a+b)/(a-b)

Using componendo dividendo rule we get

{(tanx+tany)+(tanx- tany)}{tanx+tany)-(tanx-tany)}={(a+b)+(a-b)}/{(a+b)-(a-b)}

=2tanx/2tany = 2a/2b

=> tanx/tany = a/b

Answer 2

Answer:

Yeah I am from Ap

can I get u r intro bro